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1/2 Points) DETAILS PREVIOUS ANSWERS LARCALCET7 9.6.038. Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the convergence or divergence of the series using other methods (If you need to use \infty or -\infty, enter INFINITY or -INFINITY, respectively.) $\sum_{n=1}^{\infty} \frac{(-1)^n [2 \cdot 4 \cdot 6 \cdots (2n)]}{2 \cdot 5 \cdot 8 \cdots (3n - 1)}$ $\lim_{n \to \infty} |\frac{a_{n+1}}{a_n}| = \boxed{}$ converges diverges Need Help?

          1/2 Points) DETAILS PREVIOUS ANSWERS LARCALCET7 9.6.038.
Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the convergence or divergence of the series using other methods (If you need to use \infty or -\infty, enter INFINITY or -INFINITY, respectively.)
$\sum_{n=1}^{\infty} \frac{(-1)^n [2 \cdot 4 \cdot 6 \cdots (2n)]}{2 \cdot 5 \cdot 8 \cdots (3n - 1)}$
$\lim_{n \to \infty} |\frac{a_{n+1}}{a_n}| = \boxed{}$ 
converges
diverges
Need Help?

1/2 Points) DETAILS PREVIOUS ANSWERS LARCALCET7 9.6.038.
Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the convergence or divergence of the series using other methods (If you need to use ∞or -∞, enter INFINITY or -INFINITY, respectively.)
∑n=1^∞((-1)^n [2 · 4 · 6 ⋯ (2n)])/(2 · 5 · 8 ⋯ (3n - 1))
limn →∞ |(an+1)/(an)| =
converges
diverges
Need Help?

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