Determine ??¹{F}. F(s) = —3s² - 18s - 6 / ((s + 2)²(s + 5)) ??¹{F} =
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We are given the equation: 3s^2 + 18s - 6F(s) = (s + 2)^2(s + 5) Now, we need to solve for F(s): 6F(s) = 3s^2 + 18s - (s + 2)^2(s + 5) Divide both sides by 6: F(s) = \frac{1}{2}(3s^2 + 18s - (s + 2)^2(s + 5)) Now, we need to find the inverse Laplace Show more…
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