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Determine if each of the following functions from {a, b, c, d} to itself is one-to-one and/or onto. Check ALL correct answers. (a) f(a) = b, f(b) = a, f(c) = c, f(d) = d A. onto. B. one-to-one. C. neither one-to-one nor onto. f(a) = d, f(b) = a, f(c) = c, f(d) = b A. one-to-one. B. neither one-to-one nor onto. C. onto. f(a) = c, f(b) = d, f(c) = a A. neither one-to-one nor onto. B. one-to-one. C. onto.

          Determine if each of the following functions from {a, b, c, d} to itself is one-to-one and/or onto.
Check ALL correct answers.
(a) f(a) = b, f(b) = a, f(c) = c, f(d) = d
A. onto.
B. one-to-one.
C. neither one-to-one nor onto.
f(a) = d, f(b) = a, f(c) = c, f(d) = b
A. one-to-one.
B. neither one-to-one nor onto.
C. onto.
f(a) = c, f(b) = d, f(c) = a
A. neither one-to-one nor onto.
B. one-to-one.
C. onto.
        
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Determine if each of the following functions from a, b, c, d to itself is one-to-one and/or onto.
Check ALL correct answers.
(a) f(a) = b, f(b) = a, f(c) = c, f(d) = d
A. onto.
B. one-to-one.
C. neither one-to-one nor onto.
f(a) = d, f(b) = a, f(c) = c, f(d) = b
A. one-to-one.
B. neither one-to-one nor onto.
C. onto.
f(a) = c, f(b) = d, f(c) = a
A. neither one-to-one nor onto.
B. one-to-one.
C. onto.

Added by Felipe F.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Determine if each of the following functions from {a, b, c, d} to itself is one-to-one and/or onto. Check ALL correct answers. (a) f(a) = b, f(b) = a, f(c) = c, f(d) = d onto, one-to-one, neither one-to-one nor onto. (b) f(a) = d, f(b) = a, f(c) = c, f(d) = b one-to-one (c) f(a) = c, f(b) = d, f(c) = a neither one-to-one nor onto, onto
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Transcript

-
00:01 Hello everyone, let's solve the given question.
00:02 So, according to the question in the part 1st, 1, 2, 1 and on 2, it is because the each element have different images and range is equal to co -domain.
00:31 Now, moving to part 2nd, then it is neither 1, 1 nor on 2, it is because a and c have same image, b and range is not equal to co -domain...
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