( x=y^{2}-y-6 ) and ( x=2 y+4 )
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Step 1:** Find the intersection points of the curves by setting them equal to each other: \[y^2 - y - 6 = 2y + 4\] \[y^2 - 3y - 10 = 0\] \[(y - 5)(y + 2) = 0\] \[y = -2, 5\] ** Show more…
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