00:01
Let's solve this question.
00:01
In this question, we have given that the computer is repaired in 5 hours is 30 % times of faulty computers is repaired in 2 hours.
00:19
So, here we can say that let x that will be a poisson's distribution variable with the parameter lambda.
00:31
So, here we can write here we need to find the value of lambda that is equals to question mark and here we can write the probability of x is equals to x that is equals to e raised to minus lambda multiplied by lambda raised to x that will be divided by x factorial.
00:53
Well, here probability of x is equals to 5 that is equals to we can write 30 % of probability of x is equals to 2.
01:04
So, therefore, that implies that probability of x is equals to 5 that is equals to 0 .3 multiplied by probability of x is equals to 2.
01:13
So, therefore, that implies that here we can write e raised to minus lambda multiplied by lambda raised to 5 divided by 5 factorial is equals to 0 .3 multiplied by e raised to minus lambda multiplied by lambda raised to 2 that will be divided by 2 factorial.
01:33
So, therefore, that implies that we will get lambda cube that is equals to 1 .8.
01:38
So, that implies that lambda that is equals to 1 .2164.
01:43
So, this will be our mean time taken that is the required answer and here we have given that and let us say x that be the length of time and here we can say that x that follows the exponential distribution with theta parameter and here we can write f of x is equals to theta multiplied by e raised to minus theta x for x is greater than 0 and that is equals to 0 for otherwise...