00:01
You can see the gel photos.
00:01
So i actually searched online and found some of the sample photos regarding this question about the allu -1 element.
00:10
So what we know about this is the allu element from chromosome 9 and 11.
00:16
So they are amplified in, obviously, pcr reaction.
00:20
So if there is an insertion of allu element in this chromosome 9, it will actually generate a band that has a different size from the band, from the pcr product that doesn't have allu element inserted.
00:39
And the same with chromosome 11.
00:42
So if there's insertion without insertion and with insertion, the pcr product will have different sizes.
00:49
So what we know about the chromosome 9 and 11 is that if you have a chromosome 9 insertion, without the allu element insertion, the pcr size is around 193 base pair.
01:11
So this is talking about pcr product.
01:14
And with the insertion allu -1, you have a size around 523 base pair.
01:24
Now, when it comes to chromosome 11, again, the pcr product have two different sizes.
01:35
Without the insertion, the size of the pcr product is around 309 base pair.
01:44
With the insertion of this element, now the size increased to about 631 base pair.
01:53
So the question, obviously, asks you to figure out, on this gel, do you have different samples? one line is, say, individual number 1.
02:05
And then each individual has two different samples.
02:08
One is the pcr product from chromosome 9, and the other is from chromosome 11.
02:13
They obviously have different primers.
02:15
So then you can see that each individual has two different samples.
02:18
One is about chromosome 9.
02:20
The other is about chromosome 11.
02:22
So we have four different individuals.
02:24
And so the question says, use a table, obviously, to indicate a genotype of either insertion or deletion for the element for each individual.
02:38
So in this case, let's take a look.
02:40
The letter is in the middle.
02:41
So this is the 100 base pair letter.
02:45
So i assume the one that is lowest is 100.
02:48
So this band here is 100.
02:50
So you can count.
02:51
So you can tell that this band here is around 200.
02:55
So this corresponding to 193 base pair band.
03:01
And then in the second lane, which is the individual with chromosome 11, you see two bands.
03:07
So if you look at the size of the letter, so if this red one is 100 base pair, then you can count up.
03:14
So that second one is obviously 200, 300, 4, 5, 6, 7, 8, 9, 10, 11.
03:22
So we can see each bar or band is 100 base pair longer than the one that below it.
03:29
So from there, we can also decide that, let's say, this is 193, which corresponding to about 200 base pair.
03:36
The band in the second lane with chromosome 11, this one here, most likely is 300.
03:44
So this is probably 309 base pair band right here.
03:55
Now, what about the one on top in the second lane? this band, if you count all the way up, is slightly above this green band here.
04:06
This one should be about 630.
04:13
This is slightly above 600 base pair.
04:17
So this is this band right here.
04:20
So let's take a look at individual one first, and then we can go along.
04:24
So for individual number one, you see only one band in 193.
04:31
And you don't see any longer band at around 523.
04:37
So for each individual, we are diploid, which means that we have two chromosome 9, one inherited from the mother, the other inherited from the father.
04:49
So this means that that person is homozygous for deletion for allele one.
04:55
So let's write down individual one.
05:10
So for chromosome 9, both alleles will be deletion...