00:01
We are asked to calculate the boiling point of a 3 .5 % by mass solution of sodium chloride in water.
00:09
Okay, the first thing i'm going to need to do is figure out the molality of the nacl.
00:23
We will do that by taking the moles of our solute or the mass of our solute plus the mass of our solution or solvent, sorry, equals the mass of our solution.
00:49
And if i let this be equal to 100 and this is, did i say 3 .5? 3 .5, my mass of my solvent is 96 .5 grams, grams, and grams.
01:16
So now we can calculate as follows.
01:21
Our molality will equal our 3 .5 grams of our solute times 58 .5 grams per mole divided by, and then i'm going to just keep going here, and this is going to be over 96 .5 grams of solvent, and we have 1 ,000 grams per kilogram, and that should be good...