00:01
Dear students, we have to calculate the percentage of chloride in the water sample.
00:05
Water sample is 10 gram silver -nated solution conjured to titrate with this sample is 4 .33 gram.
00:12
Consenation of silver -nated solution is given 2 gram silver -nated per 25 gram solution.
00:19
So let us find out in 4 .33 gram how much silver -nated is there? and from equation we will calculate how much chloride is reacting with how much of silver -nithed.
00:30
So, let us see, first 25 gram of solution contains 2 gram silver nitrate.
00:46
Therefore our solution consumed is 4 .33, so 4 .33 solution contains silver nitrate 2 .0 multiplied by 4 .33 divided by 25.
01:07
Equal to 0 .3464 gram ag no3.
01:18
Now let us write the equation cl minus plus ag no3 gives rise to agcl plus no3 minus.
01:32
Now here 1 mole of chloride rears with 1 mole of silver nitrate.
01:37
So chloride is 35 .5 gram, silver nitrate is 108.
01:42
Silver, nitrogen is 14, oxygen is 48, which is equal.
01:46
Silver nitrate is 170 gram.
01:48
That means when silver knight is 170 gram, chloride is how much? 35 .5 gram...