00:01
Okay, for this question, first we can determine the forces a joint a.
00:10
So from sigma fz equal to zero, we can have that fab times 6 divided by the square root of 29 minus 10 is equal to 0.
00:23
So fab is 6 .29 kilo newton and at this tensile force, for sigma fx equal to 0 can have that fac time 2 divided by 5 minus fat time distance is equal to 0 so that means fac is equal to fad and for sigma if y equal to 0 have that f ac t time 5 divided by 6 plus f a d time 5 divided by 6 minus f a b time 3 right by the square root of 29 is equal to 0 or we have that f a c plus f a d is equal to 4 .2 and we give this equation 1 and this equation 2 from equation 1 and equation 2, we can find that f -a -c, which is equal to f -a -d, that will be 2 .1 kilo -newton as a compressive force.
02:02
And joint b, we take sigma force in x -direction equal to 0.
02:11
Have that f -b -c, time 2, divided by square root 38, minus f -e -r, 3 ,000.
02:19
Bt time 2 divided by the square root of 38 equal to 0 so that f bc is equal to f bt give that the third equation and if we give sigma f z equal to 0 have that f bc plus f bt time 6 by the square root of 38 minus fab times 6 divided by the square root of 29 equal to 0.
02:58
And that means fbc plus fbd is equal to 7 .12...