Determine the integral \(I = \int \frac{1}{\theta^2} \left( 4 \cos \left( \frac{1}{\theta} \right) - \frac{2}{\theta} \right) d\theta\) 1. \(I = -\frac{1}{\theta^2} - 4 \sin \left( \frac{1}{\theta} \right) + C\) 2. \(I = -\frac{1}{\theta^2} - 4 \cos \left( \frac{1}{\theta} \right) + C\) 3. \(I = \frac{1}{\theta^2} + 4 \cos \left( \frac{1}{\theta} \right) + C\) 4. \(I = \frac{1}{\theta^2} - 4 \cos \left( \frac{1}{\theta} \right) + C\) 5. \(I = \frac{1}{\theta^2} + 4 \sin \left( \frac{1}{\theta} \right) + C\) 6. \(I = \frac{1}{\theta^2} - 4 \sin \left( \frac{1}{\theta} \right) + C\)
Added by James V.
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Step 1: Rewrite the integral as: I = ∫ (1/θ^2)(4cos(1/θ) - 2/θ) dθ Show more…
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