00:01
Now to determine the lateral loads at the point al and sl at the outside front wheel when the vehicle is at incipit and throwover, we need to calculate the forces acting on the vehicle and use the equation of static equilibrium.
00:19
First, let's identify the forces and distances involved.
00:23
Total weight of a vehicle is 2500 lbs and cg height h is 24 inches that means it is approximate 2 feet.
00:38
Then friction coefficient mu is equal to 0 .3 and a is equal to 47 inches that means it is equal to 3 .92 feet.
00:54
It is the distance from cg to the real axle.
00:59
B is equal to distance from cg to the front axle it is given as 54 inches that means it is equal to 4 .5 feet.
01:13
Then t is equal to 62 inch it is the track width it is equal to 5 .17 feet.
01:24
After that r is equal to 13 inches which is equal to 1 .08 feet and it is the height of a cg above the road surface.
01:37
Then c is equal to 3 inches which is equal to 0 .25 feet it is the distance from cg to the lateral axis.
01:48
Then d is equal to 22 inch it is equal to 1 .83 feet it is the distance from lateral axis to the outside wheel.
01:58
Now let's determine the lateral load at the points an and sl at the incipitant rollover.
02:06
Then calculate the lateral load at the lo.
02:11
Lateral load is denoted by lo due to the vehicle's weight transfer during cornering.
02:17
So, this is equal to weight multiplied by h upon t that means lo is equal to 2500 lb into h that is 2 divided by 5 .17 feet.
02:32
So, this is equal to 966 .38 lb.
02:39
So, this is required lateral load transfer.
02:42
Now calculate the lateral load at outside the front wheel.
02:47
So, this is equal to lo a divided by t.
02:53
This is equal to 966 .38 multiplied by 3 .92 divided by 5 .17.
03:04
Therefore, l is equal to 734 .19 lb that means 734 .19 pounds.
03:13
Now calculate the lateral load at the point al that is rear outside wheel due to the weight transfer and friction...