Determine the magnitude and direction of the force on an electron traveling 8.56×10^5 m/s horizontally to the east in a vertically upward magnetic field of strength 0.33 T.
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Step 1
6 x 10^-19 C), v is the velocity of the electron (8.56 x 10^5 m/s), and B is the magnetic field strength (0.33 T). Show more…
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