00:01
All right.
00:01
So we're looking at, to figure out the oxidation number, we basically just have to figure out the charge of everything else and compared to the overall charge.
00:11
So the nh3s have a zero charge.
00:15
There's five of them.
00:16
And then we have one bromine, which has a negative one.
00:19
So how do we get from negative one to a total charge of plus two? the cobalt has to be in the oxidation state of plus three so that the charge is equal plus two overall.
00:31
For part b, each cyanide is negative 1, and there's six of them, so we have a negative 6.
00:37
The overall charge is negative 4, so that means that iron has to be plus 2, because 2 minus 6 give you negative 4.
00:46
Then we have oxalate, and there's 3 of them, so it's going to be, each of them is negative 2.
00:52
That's negative 6 overall.
00:54
So from negative 6, again, we have negative 4 total, so cobalt is in the plus 2 oxidation state.
01:01
Lastly, we have four chlorines here bonded to the palladium.
01:05
Each is negative one.
01:06
So that's going to be negative four...