00:01
Hello students hope you are doing it.
00:04
In this video we will calculate the ph of buffer for which the concentration of base is given as 0 .25 mole.
00:17
Concentration of salt is given as 0 .10 mole.
00:29
Kb is equals to 1 .8 into 10 rest to the power minus 5 and we have to find ph for the given buffer.
00:41
Now we know p -o -h is equals to p kb plus log of concentration of salt divided by concentration of base.
01:04
So let's put the values into the equation.
01:07
We know that p kb is equals to minus log of kb plus log of salt.
01:17
Divided by concentration of base minus log of the value of kb is 1 .8 into 10 rest to the power minus 5 plus log of concentration of salt is 0 .10 and concentration of base is 0 .25.
01:42
Solving this we have log log of 1 .8 into 10 rest to the power minus 5 as minus 4 .4.
01:54
4 .744 plus log of 0 .10 divided by 0 .2502.
02:03
It is log of 0 .4...