What is the pH of a solution prepared by mixing 50.00 mL of 0.10 M NH3 with 10.00 mL of 0.10 M NH4Cl? Assume that the volume of the solutions is additive and that Kb = 1.8x10^-5 for NH3.
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Step 1
Calculate the moles of NH3 and NH4Cl in the solution. moles of NH3 = 0.10 M * 0.050 L = 0.0050 mol moles of NH4Cl = 0.10 M * 0.010 L = 0.0010 mol Show more…
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