00:01
Hi, here in this given problem there is a complicated looking circuit diagram, mixed grouping of resistors first of all two resistors in parallel combination here.
00:13
These two are in parallel which are r2 and r3 and r4 is in series with them.
00:24
Then with this parallel combination and series combination another resistance, r5 that is in parallel with this upper branch r5 and then r1 this is in series with this complete network and a potential has been applied here a source has been applied here source voltage and there is a voltmeter v put across r5 and we have to measure the reading of this volt meter.
01:08
Means actually we have to find the potential drop across r5 and as r5 is in a parallel combination.
01:17
So whatever the potential drop will be there across this parallel combination, the same potential drop will be across r5 because we know potential remains same in parallel.
01:26
So the same will be the reading of this r5.
01:29
So actually what we have to do, we have to find the potential drop approach this parallel combination.
01:37
Now the values of the resistors r1 is 5 om, r2 this is 4 .4 om, r3 is 7 .7 om, this is 4 .5 om and at last r5 this is 4 .8 ome and the potential applied overall potential this is 8 .2 volt now to find potential drop across this network parallel network we should have an idea about the current here in this circuit and to find the total current we should have the value of total resistance so we start finding it first of all these r2 and r3 are in parallel so the net resistance will be given by as r2 and r r r 3 are in parallel so their net resistance will be given by let it be r p p stands for parallel r p1 this is first parallel grouping of the circuit r p1 and we know when only two resistors are in parallel the shortcut is shortcut to find their value numerator their product and in denominator their addition like this.
03:07
So here this r p1 that will be given by 4 .4 multiplied by 7 .7 divided by 4 .4 plus 7 .7 and it is calculated to be equal to 2 .8 om.
03:24
Now this r p1 here this it is in series with r4 so this r p1 is this r p1 is in series with r4.
03:45
So this series combination, let it be rs1, the first series of the circuit, that will be given as rp1 plus r4.
03:56
Means this is 2 .8 plus 4 .5 om and it will come out to be equal to 7 .3 om...