00:01
Hi, thank you for your question.
00:03
Here, the circuit looks like this.
00:07
So the question is, first, coalesced the current shown on the m meter, give your answer to a precision of 1 millie amps.
00:18
We're given u is 10 .7 volts.
00:28
And the r -1 is 10 .8 oms.
00:36
And r -sub 2 is 54 oms.
00:57
The volt meter shows a rating of 4 .0.
01:10
Okay, so an r sub three, what is r sub three? okay, r sub three is a question for a second part.
01:24
So now let's find the current show on the m meter, okay? so this is what we want to know.
01:36
Okay, now let's reconstruct or rewrite, redraw this circuit okay so here is r sub 1 you have r sub 2 and r sub 3 for r sub 2 we have an m meter right and we also have a voltmeter where's the volt meter the volt meter is between here and here okay okay and here is you okay so if we use u to minus readings at the volt meter, we got 10 .7 volt minus 4 .0 volts.
03:17
We got 6 .7 volt.
03:20
6 .7 volt is the volt for the two resistors.
03:28
Okay.
03:35
We know these two resistors, r -sub 2 and r -sup 3, are in parallel.
03:50
Okay, so by the property of parallel circuits, okay.
03:56
We know that the voltage at v2 okay so let's call this uv2 okay also equal to 6 .7 volt so now we can find oh i think this is a ur 2 you you v2 it should be u r 2 so the radins on the emmeter i sub a equal to i r s up r which equals to u r divided by r r which is 6 .7 volt divided by r sub 2.
05:01
We know this is 54 oms.
05:07
So the result is, let's use a calculator.
05:29
So you got that, it's actually 0 .1271.
05:57
Amps or, that's the requirement of the, we should round this to 1 millie amps...