Determine the resistivity of a silicon sample ($n_i = 10^{10} \text{cm}^{-3}$) if doped with: (a) donor with a concentration of $5 \times 10^{15} \text{cm}^{-3}$, and (b) donor and acceptor each of a $5 \times 10^{15} \text{cm}^{-3}$ concentration.
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6 x 10^-19 C) - \( n \) is the electron concentration - \( p \) is the hole concentration - \( \mu_n \) is the electron mobility - \( \mu_p \) is the hole mobility Show more…
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A silicon crystal having a cross-sectional area of $0.001 \mathrm{~cm}^{2}$ and a length of $10^{-3} \mathrm{~cm}$ is connected at its ends to a $10-\mathrm{V}$ battery. At $T=300 \mathrm{~K}$, we want a current of $100 \mathrm{~mA}$ in the silicon. Calculate ( $a$ ) the required resistance $R,(b)$ the required conductivity, (c) the density of donor atoms to be added to achieve this conductivity, and $(d)$ the concentration of acceptor atoms to be added to form a compensated p-type material with the conductivity given from part $(b)$ if the initial concentration of donor atoms is $N_{d}=10^{15} \mathrm{~cm}^{-3}$
The concentration of donor impurity atoms in silicon is $N_{d}=10^{15} \mathrm{~cm}^{-3}$. Assume an electron mobility of $\mu_{n}=1300 \mathrm{~cm}^{2} / \mathrm{V}-\mathrm{s}$ and a hole mobility of $\mu_{p}=450 \mathrm{~cm}^{2} / \mathrm{V}-\mathrm{s}$. (a) Calculate the resistivity of the material. ( $b$ ) What is the conductivity of the material?
The concentration of donor impurity atoms in silicon is Nd = 1015 cm-3. Assume an electron mobility of µn = 1300 cm2/V-s and a hole mobility of µp = 450 cm2/V- s. (a) Calculate the resistivity of the material. (b) What is the conductivity of the material?
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