Question

Determine the temperature of a reaction if ΔrG° = 6.21 kJ mol-1, ΔrG = -8.34 kJ mol-1, and Q = 0.0100. 380 K 49.6 K 273 K 448 K 298 K

          Determine the temperature of a reaction if ΔrG° = 6.21 kJ mol-1, ΔrG = -8.34 kJ mol-1, and Q = 0.0100.

380 K
49.6 K
273 K
448 K
298 K
        

Added by Yolanda A.

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Determine the temperature of a reaction if ΔrG° = 6.21 kJ mol-1, ΔrG = -8.34 kJ mol-1, and Q = 0.0100. 380 K 49.6 K 273 K 448 K 298 K
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Transcript

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00:01 Hey, welcome to the video, we know that delta g is equal to delta g0 plus rt long cube.
00:05 And on substituting the known values, we would have minus 8 .34 kilojoule per mole is equal to 6 .21 kilojoule per mole.
00:21 This plus 0 .00831.
00:25 This is the gas constant in kilojoule per mole per kelvin into t that is the temperature we have to find into lawn q which is 0 .01 from this we would get minus 14 .55 kilojoule per mole that is if 6 .21 kilojoule per mole this move towards the left we would get minus 14 .55 kilojoule per mole inverse is equal to 0 .008314 kilojoule per mole per kelvin into t and the value of long 0 .01 is equal to minus 4 .605 and from this t would be equal to 14 .55 kilojoule per mole divided by 0 .008314 kilojoule per per kelvin into 4 .6051...
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