Question

DATA TABLE Volume NaOH (mL) | Volume acid (mL) | Temperature change (°C) 00.3 | 00.3 | 30.0 mL | 30.0 mL | 22.0 - 27.3 °C = 5.3°C 0.015 mL | 0.045 mL | 22.4 - 24.7 °C 2.3 0.045 mL | 0.015 mL | 22.1 - 29.5 °C 7.4 0.02 mL | 0.04 mL | 22.2 - 24.7 °C 2.5°C 0.04 mL | 0.02 mL | 22.0 - 28.6 °C 6.6°C

          DATA TABLE
Volume NaOH (mL) | Volume acid (mL) | Temperature change (°C)
00.3 | 00.3 |
30.0 mL | 30.0 mL | 22.0 - 27.3 °C = 5.3°C
0.015 mL | 0.045 mL | 22.4 - 24.7 °C 2.3
0.045 mL | 0.015 mL | 22.1 - 29.5 °C 7.4
0.02 mL | 0.04 mL | 22.2 - 24.7 °C 2.5°C
0.04 mL | 0.02 mL | 22.0 - 28.6 °C 6.6°C

DATA TABLE
Volume NaOH (mL) | Volume acid (mL) | Temperature change (°C)
00.3 | 00.3 |
30.0 mL | 30.0 mL | 22.0 - 27.3 °C = 5.3°C
0.015 mL | 0.045 mL | 22.4 - 24.7 °C 2.3
0.045 mL | 0.015 mL | 22.1 - 29.5 °C 7.4
0.02 mL | 0.04 mL | 22.2 - 24.7 °C 2.5°C
0.04 mL | 0.02 mL | 22.0 - 28.6 °C 6.6°C

Added by Viviana R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Hitendra Singh

11/13/2021

Step 1

Step 1: Write out the balanced chemical equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4): \[2NaOH + H2SO4 \rightarrow Na2SO4 + 2H2O\] Show more…

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