00:01
Okay, so we have these functions and we want to determine whether they're bijections from r to r.
00:06
So the first function, a, is f of x equals x squared plus 1.
00:11
And the answer here is no, because it's not injective or subjective.
00:15
So let's just show that it's not injective.
00:17
F of 1 equals 1 square plus 1, which is 2.
00:21
F of minus 1 equals minus 1 squared plus 1, which is 1, which is 2.
00:28
So we have that f of 1 equals f of minus 1, and therefore it's not injective because two points, two different points mapped to the same point.
00:38
For part b, f of x equals x square plus 1 over x square plus 2, and it's not bijective for a similar reason.
00:47
F of 1, for example, is 1 square plus 1 on the top 2, 1 square plus 2 is 3, f of minus 1 is minus 1 squared, which is 1 plus 1, which is 2.
01:00
And then on the bottom, we have minus 1 squared, which is 1 plus 2, which is 3.
01:05
So again, we have two different points.
01:07
Mapping to the same point, so not injective.
01:11
For part c, f of x equals x cubed.
01:14
So this is injective.
01:17
So this is injective and subjective, sorry.
01:20
So it's bijective, and it has inverse function.
01:23
F inverse.
01:24
We can just take the cubed root, and this is well defined for each number...