Determine whether the equation is exact. Otherwise, find an integrating factor, then solve the DE. y(2x^2-xy+1)dx+(x-y)dy=0
Added by Peggy P.
Step 1
The given equation is in the form of Mdx + Ndy = 0, where M = y(2x^2 - xy + 1) and N = x - y. The condition for exactness is that ∂M/∂y = ∂N/∂x. ∂M/∂y = 2x^2 - xy + 1 and ∂N/∂x = 1. Since ∂M/∂y ≠ ∂N/∂x, the given differential equation is not exact. Show more…
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