00:01
So for part one, where we're drawing three jacks in a row without replacement, we are going to have that this is going to be a dependent event.
00:12
Or these are going to be dependent events.
00:15
If we say, for instance, j1 is a jack, the first card, say jack, and j2 is the event that the second card is a jack, and so on, the events j1, j2, and j3 are dependent.
00:35
Particularly because we'd have the probability of getting a jack as the second card, given that we got a jack as the first card, would be equal to, actually i'll start off with just the probability of j1, getting a jack when we have the full deck of cards.
00:52
There are four jacks overall, and there are 52 cards in the deck, so that's four out of 52.
00:57
The probability of getting a jack as the second card, given that we got a jack as the first card would be equal to 3 over 51.
01:09
Whereas if we got a jack as the second card, given that we did not get a jack as the first card, that would be 4 over 51.
01:17
So that's proof enough there that the events are dependent.
01:22
That being said, the probability of getting a jack as the first, jack as the second, and a jack as the third would be equal to 4 over 52 times 3 over 51 times now probability of getting a jack third when we've already removed 2 from the deck would be 2 over 50 and calculating that probability out i'm just going to do that off screen here that's going to come out to a probability of 0 .018 then for part for part 2 the second question let's see.
02:06
We have that odds 4 can be described as the reduced ratio of probability that a particularly outcome occurs, p, divided by 1 minus p.
02:21
So that's the probability that the outcome does not occur.
02:26
And then odds against, odds against, we can think of as just being the probability that we do not win.
02:41
Or the event does not occur, 1 minus p, divided by the probability that the event does occur.
02:49
So, divide by p...