5.) Determine whether the following reaction is spontaneous at 298 K 2C(diamond) ? 2C(graphite) $\Delta H^\circ$(diamond/graphite) = -1.5 kJ $S^\circ$(diamond) = 2.38 J/(mol·K) $S^\circ$(graphite) = 5.74 J/(mol·K)
Added by Melissa U.
Close
Step 1
ΔS = S(graphite) - S(diamond) ΔS = 5.74 J/(mol*K) - 2.38 J/(mol*K) ΔS = 3.36 J/(mol*K) Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 100 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Given the reaction of diamond converting to graphite: 2C(diamond) → 2C(graphite) Determine ΔG° at 298 K and predict whether the reaction is spontaneous or not. ΔHf° = 1.9 kJ/mol (diamond) S° = 2.38 J/mol (diamond) S° = 5.74 J/mol (graphite) A) ΔG° = +2.90 kJ/mol: Non spontaneous reaction B) ΔG° = -5.8 kJ/mol: Spontaneous reaction C) ΔG° = -2.90 kJ/mol: spontaneous reaction D) ΔG° = +5.8 kJ/mol: Spontaneous reaction
Sri K.
Given the reaction of diamond converting to graphite: 2C(s, diamond) → 2C(s, graphite) Determine ΔG° at 298 K and predict whether the reaction is spontaneous or not. ΔHf° (C, diamond) = 1.9 kJ/mol S° (C, diamond) = 2.38 J/mol S° (C, graphite) = 5.74 J/mol A) ΔG° = +2.90 kJ/mol; Non spontaneous reaction B) ΔG° = -5.8 kJ/mol; Spontaneous reaction C) ΔG° = -2.90 kJ/mol; spontaneous reaction D) ΔG° = +5.8 kJ/mol; Spontaneous reaction
Given the reaction of Diamond converting to graphite 2C (s, diamond) -> 2C (s, graphite), determine ΔG at 298 K and determine if this reaction is spontaneous or not. What does this say about the rate of the reaction? (1-2 sentences). ΔHf° (C, diamond) = 1.9 kJ/mol, S° (C, diamond) = 2.38 J/(mol-K), S° (C, graphite) = 5.74 J/(mol-K).
Madhur L.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD