Question

Determine whether the planes are parallel, perpendicular, or neither. x - y - 7z = 1, \quad 7x + y - z = 6 \text{parallel} \text{perpendicular} \text{neither} If neither, find the angle between them. (Round your answer to one decimal place. If the planes are parallel or perpendicular, enter PARALLEL or PERPENDICULAR, respectively.)

          Determine whether the planes are parallel, perpendicular, or neither.
x - y - 7z = 1, \quad 7x + y - z = 6
\text{parallel}
\text{perpendicular}
\text{neither}
If neither, find the angle between them. (Round your answer to one decimal place. If the planes are parallel or perpendicular, enter PARALLEL or PERPENDICULAR, respectively.)

Determine whether the planes are parallel, perpendicular, or neither.
x - y - 7z = 1, 7x + y - z = 6
parallel
perpendicular
neither
If neither, find the angle between them. (Round your answer to one decimal place. If the planes are parallel or perpendicular, enter PARALLEL or PERPENDICULAR, respectively.)

Added by Joshua V.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert H M

Step 1

The normal vector of a plane is the coefficients of x, y, and z in the equation of the plane. For the first plane, x - y + 7z = 1, the normal vector is <1, -1, 7>. For the second plane, 7x + y + z = 6, the normal vector is <7, 1, 1>. To determine if the planes Show more…

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Determine whether the planes are parallel, perpendicular, or neither. x - y + 7z = 1, 7x + y + z = 6 O parallel O perpendicular O neither If neither, find the angle between them. (Round your answer to one decimal place. If the planes are parallel or perpendicular, enter PARALLEL or PERPENDICULAR, respectively.) Need Help?