Question

Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.) an = (-1)^n / 8 sqrt (n)

Name: determine whether the sequence converges or diverges if it converges find the limit if an answer does not exist enter dne an 1n 8 sqrt n 60116
Uploaded: 2023-08-09T20:33:13-08:00
Duration: 3 min 30 s
Channel: Supreeta N
Description: determine whether the sequence converges or diverges if it converges find the limit if an answer does not exist enter dne an 1n 8 sqrt n 60116

          Determine whether the sequence converges or diverges. If it
converges, find the limit. (If an answer does not exist, enter
DNE.)
an = (-1)^n / 8 sqrt (n)

Added by Tyler B.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Supreeta N

08/09/2023

Step 1

First, we can rewrite the sequence as: $$a_n = \frac{(-1)^n}{8\sqrt{n}}$$ Now, let's consider the absolute value of the sequence: $$|a_n| = \left|\frac{(-1)^n}{8\sqrt{n}}\right| = \frac{1}{8\sqrt{n}}$$ As $n$ goes to infinity, the denominator $8\sqrt{n}$ also Show more…

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Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.) an = (-1)^n / 8 sqrt (n)