The ratio test states that for a series \sum a_n, if lim_(n->\infty) |a_(n+1)/a_n| < 1, then the series converges. If lim_(n->\infty) |a_(n+1)/a_n| > 1 or does not exist, then the series diverges.
In this case, a_n = e^(9n/2). Let's calculate the ratio
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