Determine $\mathcal{L}^{-1}\{F\}$. $\qquad F(s) = \frac{7s^2 - 13s + 4}{s(s-6)(s-7)}$ Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. $\mathcal{L}^{-1}\{F\} = $
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Using the table of Laplace transforms, we can find that the Laplace transform of 7s^2 is 14/s^3, the Laplace transform of -13s is -13/s, and the Laplace transform of 4 is 4/s. Show more…
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