(a) The velocity of the collar is given by the derivative of the distance function with respect to time. So, we differentiate \( r=2.5 t^{3}-5 t^{2} \) with respect to \( t \) to get \( v = dr/dt = 7.5t^{2} - 10t \). At \( t=1 \) s, the velocity \( v = 7.5(1)^{2}
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