00:01
Hello, the objective is to diagonalize the matrix a, which is 4 -0 -1 -1 -0 -4 -minus 4 -2 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -0 -mine minus 4.
00:30
Now first we find the eigenvalues and the corresponding eigenvector for the given matrix.
00:46
For the eigenvalues we compute the determinant of a minus lambda i which is equals to determinant of 4 minus lambda 0 .0 .0 .0.
01:01
0 0 0 0 0 0 0 0 0 0 0 1 minus 4 minus 1 minus 4 minus lambda 0 0 and the determinant value is equal to 4 minus lambda whole square times minus 4 minus lambda whole square.
01:39
Now we equate the obtained determinant that is 4 minus lambda square minus 4 minus lambda whole square to 0 to find the value of lambda.
01:52
So lambda is equal to 4, 4 minus 4 minus 4.
02:00
So the corresponding diagonal matrix denoted by d is 4 -00 -0 -0 -400 -0 -0 -0 -0 -0 -0 -mine minus 4 -0 -0 -0 -0 -0 -0 -0 -0 -mineus 4.
02:24
Now we compute the corresponding eigenvector.
02:29
So, eigenvector corresponding to lambda is equals to 4 is minus 8, minus 4, 1, 0...