00:01
Hello students, here we have a cylinder.
00:02
In the cylinder the current i is passing and it has the radius of a.
00:08
First we have to calculate magnetic field b that is inside the cylinder.
00:26
So by using the ampere's law we can write from ampere's law surface integral of p vector dot dl vector equal to mu naught i enclosed.
00:51
So here we can write current density j vector equal to i divided by a.
01:04
This is our equation number one.
01:07
So since the current density is proportional to s square, we can write j equal to ks square.
01:14
So now we can get current i equal to integral over j da that is equal to integral of ks square d pi s square.
01:32
So we will get k pi integral over s power 4 ds.
01:41
So we will get the current as k pi s power 5 divided by 5 0 2 a that is equal to k pi a power 5 divided by 5.
02:02
So the current enclosed on the system is i equal to k pi a power 5 divided by...