00:01
Okay, and this problem i have to differentiate the function y equals secant x tangent x.
00:05
Y equals secant x tangent x.
00:08
I'm going to differentiate this using the product rule, where it says that y prime is going to be the derivative of the first times the second.
00:14
Well, the derivative of secant is going to be secant tangent.
00:18
Seekent x tangent x.
00:19
And i'm going to multiply that times the second, which is tangent.
00:22
Okay, so that's the derivative of secant.
00:24
Now we're going to multiply that times tangent x.
00:26
And then i'm going to add to that the derivative of tangent times secant.
00:30
The derivative of tangent is a secant square...