00:01
In this question, given that the equation which is ch3oh in the liquid form reacts with 3 divided by 2 moles of oxygen in the geish state to give carbon dioxide in the gasiest state plus 2 moles of water in the liquid state.
00:28
And also we have been provided with the delta g not f in the unit kg per mole values for the carbon dioxide, which is minus 394 kilojoules per mole.
00:51
The water, which is given as minus 237 kilojoules per mole.
01:02
Oh it in the liquid form so the value is minus 166 kilojoules per mole and oxygen it is zero kilojoules per mole we have to calculate the value of e not so here coming on to the solution so we know the expression for delta g so delta g is equal to epsilon np delta g not of f of the products minus epsilon n f, it is n r delta g not of the reactins.
02:20
So here we put the values so that will be 1 mole multiplied by minus 394 kilojoules per mole plus 2 mole multiplied by 237 kilojoules per mole plus 2 mole multiplied by 237 kilojoules per mole minus 1 mole minus 1 mole multiplied by minus 166 kilojoules per mole minus 0.
03:02
So we get the value of delta g which is minus 702 kilojoules.
03:15
Now also we know that delta g0 is equal to n f e0 minus nf e .0.
03:32
Now n is the moles of number of moles of electrons involved...
