00:01
Hello students so in this question we are given that the genotypes of parent generation are capital a capital a capital b small b capital c capital c and capital d small d this is a one parent and for another parent the genotype is given as capital a small a small b small b capital c small c and small d so when we cross these two parents these parents are crossed and we will get by crossing these two parents we'll get the offspring of fn generation.
00:33
So we have to tell that what is the probability of getting capital a small a capital sorry small b small b capital c small c small d or capital a capital a capital capital a small b capital c small b capital c small d what are the chances of getting these offspring as fn generation? so first of all let's take this genotype of the appendination of the offspring.
01:04
So by mendels, mandel's independent assortment law, independent assortment, we can say that the probability of getting this capital a small a from the strata hybrid cross are the same as from getting capital a small a from the mono -hybrid cross of these two genes.
01:28
Similarly, we can say that the probability of getting small b small b from these tetra hybrid crosses are the same as getting from this mono hybrid cross of capital b capital capital capital capital capital capital capital b small b small b so we will calculate the individual probabilities of getting these traits and then we will multiply these probabilities to get the probability of this whole offspring okay so first of all we will calculate the probability of getting capital a small a the fn generation if the parents are capital a capital a and capital a small a okay so we'll draw the penned square for this so the panette square will be somewhat like this here we have capital a capital a capital a and here we have capital a capital a small a so we can write it as capital a capital a capital a capital a capital a capital and here we have capital a small a so so the probability of getting capital a small a from these, these cross are 1 by 2 that is 50 % so the probability for capital a small is 1 by 2.
02:40
Similarly we'll calculate the probability for getting small b small b.
02:44
So for small b small b we'll draw another pannet square of cross capital b small b and small b small b so we'll draw the cross here we have capital b small b and here we have small b small b.
03:01
Here comes capital b small b capital b small b and here we have small b small b and small b so again this probability comes out to be 1 by 2 similarly we'll calculate the probability for capital c small c so drawing the panette square for capital c small the crosses are capital c capital c capital c capital c and capital c small c so again if we look at this capital c capital c capital c and capital c small z this crows is exact similar to this capital a capital a and capital a small a cross.
03:37
So we can already say that this capital c small c will be 1 by 2.
03:42
Its probability will be 1 by 2.
03:44
Okay, moving on to the next part that is small d small d, small d...