00:04
To solve for this, we have here, take questions.
00:07
For the first question, we are to calculate the molar mass of an unknown compound in benzene.
00:13
So we have here freezing point depression.
00:15
The formula for freezing point depression is that freezing point depression is equivalent to the vantorft factor i of the salute multiplied by the freezing point depression constant of the solvent benzene multiplied by the molality of the solution.
00:29
So malality, this is molality.
00:32
So this is moles of salute divided by the mass of the solvent in kilograms.
00:39
Okay.
00:40
So let's calculate first for the molality of the solution.
00:43
We plug in the given values here.
00:45
The freezing point depression is 2 .64 degrees celsius.
00:50
Vantaf factor for the suede, i'm going to assume 1.
00:54
Then kf is 5 .12.
00:58
This is degree celsius per molal.
01:00
Then our unknown is molality.
01:04
So m therefore is equivalent to 0 .516.
01:08
This is molal.
01:10
So remember that molality is molalute per kilogram solvent.
01:14
So i'm going to equate 0 .516.
01:17
I'm going to write this is moles per kilogram.
01:20
Moles of solute.
01:22
Okay, let's assign first a variable to our unknown.
01:25
Let x as the molar mass.
01:29
Molar mass of compound, a known compound.
01:40
Okay, so that means if we have 25 .6 grams, we will divide this by the molar mass of the compound x, and then divide this further by the mass of our solvent benzene, 0 .250 kilograms.
01:56
Okay, so we solve for x, x will be equivalent to 198 .45.
02:03
This is grams per mole.
02:06
Okay, this is the answer to the first question.
02:09
And then for the second question, we are to calculate the freezing point of the solution.
02:17
So from the equation, the freezing point depression constant, t .f is equivalent to the freezing point of the pure solvent, minus the freezing point of the solution...