Dissolving 1.10 g of an unknown compound in 75.22 g of benzene reduces its freezing point from 5.53 \deg C
to 4.92 \deg C. What is the molar mass of the unknown compound? Kf benzene = −5.12 \deg C.
g/mol
4. If the freezing point depression of a 0.10 m aqueous solution of a solute can be expressed as
\Delta Tf = −i0.186 \deg C. For the group of solutes given, which freezing points correctly matches the solutes
dissolved in water? Kf for H2O = −0.186 \deg C/m
A. CH3CH2OH, \Delta Tf = −0.930 \deg C
B. MgSO4, \Delta Tf = −0.186 \deg C
C. NH4NO3, \Delta Tf = −0.774 \deg C
D. CaCl2, \Delta Tf = −0.558 \deg C
E. C6H6, \Delta Tf = −0.297 \deg C