Question

The strength of a patient's reaction to a dose of x milligrams of a certain drug is $R(x) = 4x \sqrt{11 + 0.5x}$ for $0 \le x \le 160$. The derivative $R'(x)$ is called the sensitivity to the drug. Find $R'(50)$, the sensitivity to a dose of 50 mg. $R'(50) = $

          The strength of a patient's reaction to a dose of x milligrams of a certain drug is $R(x) = 4x \sqrt{11 + 0.5x}$ for $0 \le x \le 160$. The derivative $R'(x)$ is called the sensitivity to the drug. Find $R'(50)$, the sensitivity to a dose of 50 mg.
$R'(50) = $

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The strength of a patient's reaction to a dose of x milligrams of a certain drug is R(x) = 4x √(11 + 0.5x) for 0 ≤ x ≤ 160. The derivative R'(x) is called the sensitivity to the drug. Find R'(50), the sensitivity to a dose of 50 mg.
R'(50) =

Added by Cheryl S.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solved by Expert Dheeraj

02/05/2022

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Step 1: The given dose is 50 mg. Show more…

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dose of 50mg. R^(')(50)= Need Help R50=32.333 dose of 50 mg. X

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