Question

Draw the circuit for the equation below by hand and then with Quartus using only the positive logic gates (i.e., AND, OR, NAND, NOR, and NOT gates) and active-high inputs and output. W = /[ (A + /B) * /(/C * D) ] (2) Do not simplify or otherwise manipulate the equation. PLEASE DRAW THE CIRCUIT TO UNDERSTAND BETTER

          Draw the circuit for the equation below by hand
and then with Quartus using only the positive logic gates (i.e., AND, OR, NAND, NOR,
and NOT gates) and active-high inputs and
output.
W = /[ (A + /B) * /(/C * D) ] (2) Do not simplify or
otherwise manipulate the equation. PLEASE DRAW THE CIRCUIT TO UNDERSTAND BETTER
        
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Added by Emily K.

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Draw the circuit for the equation below by hand and then with Quartus using only the positive logic gates (i.e., AND, OR, NAND, NOR, and NOT gates) and active-high inputs and output. W = /[ (A + /B) * /(/C * D) ] (2) Do not simplify or otherwise manipulate the equation. PLEASE DRAW THE CIRCUIT TO UNDERSTAND BETTER
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Transcript

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00:01 Hi, this is a function based on logic gates where we are given with the first function.
00:07 So f is equal to a b bar plus b c.
00:12 So we have so we have here we have b bar as a not gate.
00:17 So let this be a let this be b.
00:20 So here b is changed to b bar.
00:23 So a b and this is b so then there is a multiplication.
00:28 So we use and gate and there is another b c.
00:34 So here b so it is taken b and c again there is a multiplication.
00:40 So an and gate so it is subjected to addition.
00:43 So we have to take or gate.
00:47 So this is so this is b c and this is a b bar.
00:51 So we have the output as f is equal to so while subjecting to or gate we have a b bar plus b c.
01:00 Then for the second part we have a plus b bar into c bar plus d.
01:08 So we have four variables here a and b and here c and d.
01:12 So we have a as it is and b changes to b bar...
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