00:01
The question says so here we have been given certain scenarios with phage and the bacteria.
00:08
The first scenario is if the phage and bacteria are mixed and they are introduced into a solution containing phosphorus 35 then what will happen? so phosphorus 35 is a radioactive element.
00:25
Okay, it is an isotope of the phosphorus molecule.
00:30
So if the phage and bacteria is already mixed, then the phage will have already been absorbed on the surface of the bacteria.
00:40
That is, it's target molecule, right? so pages are nothing but the viruses that infect the bacteria.
00:47
So if they are already premixed, the phage will absorb on the surface of the bacteria and injects its dna inside, bacteria.
00:56
Hence the dna of the page will not be labeled here by the p 35 isotope that has been present in the solution.
01:05
Okay.
01:06
So the viral part of the phage or the viral part of the experiment is not at all labeled here.
01:15
Okay so option d will be the correct answer that is nothing could occur and no viral molecules could become labeled.
01:24
Okay so nothing will occur that no changes will occur in the experiment no viral molecules that is the dna of the virus will not be labeled if the radioactive p35 so this was the answer for the first question so in the second question they have asked if the phage is introduced into the p32 solution what will happen okay so here the dna of the phage that is having the phosphate molecule p .o.
01:56
4 .3 minus, right? so, which will impart the negative charge or the negative charge to the dna molecule.
02:06
So what happens is that the p32 molecule will now get incorporated into the phage dna because the dna, when it replicates, it incorporates this phosphorus from the growing medium, which will be utilized by the viral phage to multis.
02:25
Reply.
02:26
So that is why the radio activity will be seen inside the phage where the dna is present.
02:33
So the correct answer will be option b, the viral dna or the virus dna would get raped or labeled.
02:40
So this was the answer for the second part of the question.
02:43
In the third part of the question we have been asked if the phage and bacteria that is the host is mixed and introduced into a sulfur 35 medium, what will be the scenario? so, sulfur, as we all know, is a constant of a protein molecule.
03:02
And the phage is made up of dna and proteins, right? and the phage code, whatever is present, is made up of protein.
03:10
And protein as we know, has sulfur.
03:13
So what happens here is that the coat of the phage, which is made up of protein, remains outer because it is only the genetic material that has gone inside the bacteria, right? so even after the infection, the coat remains outside and hence this coat will imbibe the sulfur 35 that is present in the media and will get radio labeled...