E 2 3i times 6 i solve this problem as a bi

Name: e 2 3i times 6 i solve this problem as a bi
Uploaded: 2022-09-30T18:18:58-08:00
Duration: 4 min 9 s
Channel: Khushbu Rani
Description: e 2 3i times 6 i solve this problem as a bi

Transcript

00:01 Hi, that is a question which says that i have to find modulus of z equal to 1 minus aorta raised to the power 6, 1 plus 2 aorta raised to the power 5 divided by 3 minus iata raised to the power 8.

00:21 So it's a modulus.

00:22 I will be using the formula that modulus of z1 raised to the power n equal to z.

00:37 1 modulus raised to the power n so z modulus will be modulus of 1 minus iota raised to the power 6 1 plus 2 aorta raised to the power 5 divided by 3 minus iata raised to the power 8 so we also know that z1 z2 mod equal to z 1 mod into z2 mod so from there first it will be 1 minus iota mod raised to the power 6.

01:15 1 plus 2 iota mod raised to the power 5 divided by 3 minus iota mod raised to the power 8.

01:24 Now modulus of a plus iota b equal to a square plus b square under root.

01:35 So this is 1 square plus 1 square under root, raise to the power 6.

01:41 Multiplied by 1 square plus 2 square under root raised to the power 5 divide by 3 square plus 1 square under root raised to the power 8 so this is under root 2 raise to the power 6 under root 5 raised to the power 5 under root 10 raised to the power 8 so that would be 8 into this will be 25 under root 5 divided by 10 raised to the power 4 that is 10 into 10 into 10 4 times 4 2 times 2 5 times its value would be under root 5 by 50 okay part b or 8 number and it write in the form of a plus b aorta first of all we know that e x equal to e.

03:01 0 .0 .0.

03:02 Theta means cost theta plus iata sine theta...

Question

e^(-2-3i) times (6 + i) solve this problem as a + bi

Question

e^(-2-3i) times (6 + i) solve this problem as a + bi

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