E'° of the NAD + / NADH half reaction is - 0.32 V. The E'° of the acetoacetate / ? – hydroxybutyrate half reaction is - 0.346 V. For a redox reaction based on two redox couples, the " spontaneous " net reaction is : Hint : Use the reduction potential table. A) acetoacetate + NAD+ ? + NADH + H+ + ? – hydroxybutyrate B) NAD+ + NADH + H+ ? acetoacetate + ? – hydroxybutyrate C) ? – hydroxybutyrate + NAD+ ? acetoacetate + NADH + H+ D) ? – hydroxybutyrate + NADH + H+ ? acetoacetate + NAD+ E) acetoacetate + NADH + H+ ? ? – hydroxybutyrate + NAD+
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In this case, the E' of the NAD+/NADH half reaction is -0.32 V, which is higher than the E' of the acetoacetate/8 hydroxybutyrate half reaction, which is -0.346 V. Show more…
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