00:01
So if we identify the cumulative voltage across both battery sources with respect to the orientation of the branch currents i -1, i -2, i -3, we can reduce the current concentration from both batteries as a series relationship.
00:28
So we know that series circuits maintain constant current while having cumulative voltage.
00:37
So the 1 and 5 oom resistor at the adjacent right lower section of the circuit are making a parallel relationship.
00:49
So using the product sum rule, we can combine these two parallel resistors to do a total resistance mesh analysis.
01:01
And so that and that brings all the rest of the resistors into a series relationship.
01:07
So we have 16 .83 oom total resistance.
01:14
Now if we reverse this and get our circuit back here, we can see that the individual current publications through i1, i2, i3 as a branch current function are orientated in the given clockwise propagation from positive to negative, so that is a dc electrical.
01:48
Circuit positive to negative flow and so then the totality of the current discharging off both positive terminals of the battery reduces down to i1 or i will say i by itself rather than i 1 i 2 i 3 so this i represents the total current of the circuit so the question essentially is asking what is the total current of the circuit so based on om's law we know that when we do mesh analysis on a parallel circuit, that we would divide the voltage, constant voltage across the parallel circuit into the individual resistances to then calculate the current drop on parallel circuit.
02:31
With the series circuit, we are then using the product rule of om's law to multiply the constant current times of resistance to calculate the voltage drop or reduction from the source...