(1 point) Find the inverse Laplace transform $f(t) = \mathcal{L}^{-1} \{F(s)\}$ of the function $F(s) = \frac{e^{-2s}(9s - 7)}{s^2 + 16}$. You may use $h(t)$ for the Heaviside step function.
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The inverse Laplace transform of s^2 is t^2. The inverse Laplace transform of 16 is 16. Show more…
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