00:01
Hi, here i have the solar filling problem.
00:02
First i have to find the gradient resistance.
00:05
Let's make the sketch.
00:24
So here i labeled each resistance.
00:29
And now let's find r1.
00:31
R1 2 that's sum of 20 and 50 oms, which is 70 oms.
00:40
Now let's find r2 3.
00:46
That is 40 plus 20 oms, which is 60 oms.
00:54
Sorry that's r34 and now let's find r56 r56 is 70 plus 20 oms which is 90 oms and now let's find r3456 negative 1 so that's 1 over 60 plus 1 over 90 oms hence of course it's negative 1 r3456 is usually that which is 36 oms.
01:34
So now i can find the equivalent resistance finally.
01:40
That is the sum of r1, r2 and r3456...
