00:01
In this question, we are given this circuit, a 48 -volt battery with 4 resistors.
00:08
We want to find the equivalent resistance, current through each resistor, and the power supplied by the battery.
00:14
Okay, so to find the equivalent resistance in part a, we recognize that this is a series circuit with r1 and a parallel with a parallel connection of r2, r3 and r4.
00:34
Okay, so the equivalent resistance, here you can calculate directly by doing this r1 plus 1 over r2 plus 1 over r3 plus 1 over r4 and take the reciprocal of that.
00:51
So put in the numbers and the answer is 18 .5 oats, okay, so this is the answer for part a.
01:10
Next, we want to find a current through each battery.
01:14
So the current through battery is equal to emf divided by the equivalent resistance.
01:30
So 48 divided by 18 .5, you get 2 .59 ampere.
01:39
Then i1 is the current through the circuit, which is 2 .59 ampere, is in series with the battery...