Electric field of a single point charge: The electric field 1.5 cm from a very small charged object points toward the object with a magnitude of 180,000 N/C. What is the charge on the object? ($k = 1/4\pi\epsilon_0 = 8.99 \times 10^9 N \cdot m^2/C^2$) (A) -4.5 nC (B) -5.0 nC (C) +5.0 nC (D) +4.5 nC
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Step 1: The electric field due to a point charge is given by the formula: $$E = \frac{kQ}{r^2}$$ where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the charge. Show more…
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The electric field 1.5 cm from a very small charged object points toward the object with a magnitude of 180,000 N/C. What is the charge on the object? (k = 1/4πε₀ = 8.99 × 10⁹ N · m²/C²) A) -5.0 nC B) +5.0 nC C) -4.5 nC D) +4.5 nC
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Electric field of a single point charge: The electric field 1.5 cm from a very small charged object points toward the object with a magnitude of 180,000 N/C. What is the charge on the object? (k = 1/4πε₀ = 8.99 × 10⁹ N ⋅ m²/C²)
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