00:01
Hi, so to solve for this, we need to write first our i -stable.
00:04
If we have this acid, ha, this will dissociate to h plus and a minus.
00:12
Now for the i -stable initial change equilibrium concentration, the initial concentration is 0 .0108 molar.
00:20
The products are zero initially.
00:22
This will lose some amount, this will gain, and this will gain.
00:26
At equilibrium, we'll have 0 .0108 minus x.
00:29
This is x and x.
00:31
Since we have here the ph, we could solve for the hydrogen ion concentration.
00:36
So hydrogen ion concentration at equilibrium is equivalent to x.
00:41
So using this equation, h plus is equivalent to 10 raised to the power of negative ph.
00:48
And plug in the information that we have, that's 2 .56.
00:52
This will be 2 .75 rather times 10 to the negative 3 molar...