Question

Enter the first three non zero terms of the Maclaurin series expansion \\ $f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3$ \\ for the function $sin(5x)$

          Enter the first three non zero terms of the Maclaurin series expansion \\
$f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3$ \\
for the function $sin(5x)$

Enter the first three non zero terms of the Maclaurin series expansion

f(x) = f(0) + f'(0)x + (f”(0))/(2!)x^2 + (f”'(0))/(3!)x^3

for the function sin(5x)

Added by John G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Jaida L

07/01/2020

Step 1

f(x) = sin(5x) f'(x) = 5cos(5x) f''(x) = -25sin(5x) f'''(x) = -125cos(5x) Show more…

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Enter the first three non zero terms of the Maclaurin series expansion f(x)=f(0)+f^(')(0)x+(f^('')(0))/(2!)x^(2)+(f^(''')(0))/(3!)x^(3) for the function sin(5x) 21 for the function sin(5 x)