00:01
Hello, in this question here we need to find out this lower activation energy value.
00:05
So here we know that, that is, arrhenius equation, it states that that is k is equal to a, multiply by this exponential power of this minus ea divided by rt.
00:25
Here this r is the molar gas constant it is there.
00:29
So here the a is uncatalized.
00:34
Uncatalized it is equal to a4 catalyzed here so here we have the temperature that is equal to 37 degrees celsius which can be converted into calvin by adding this 22 -73 .15 so therefore this will become 310 .15 kelvin now here if we take the ratio of this catalyzed one with uncatalysis uncatalized here.
01:14
So therefore here it is equal to, a to a to got cancelled out here.
01:20
If we say that is a, exponential power of this e, a divided by rt, a multiplied by e, exponential power of ea divided by rt.
01:34
So these two value got cancelled out as these are equal.
01:37
So therefore here, on solving this we will have that is exponential power of this.
01:43
Minus ea activation energy of this catalyzed one.
01:48
Catalized 1 minus exponential power here it is minus e.
01:54
So ongoing denominator it will become positive.
01:57
So therefore ea value of uncatalized uncatalyzed...
