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Estimate the efficiency of aerobic cellular respiration of a molecule of glucose: a. energy of formation of atp from adp: ~ + 57 kj/mol b. energy of combustion of glucose: ~ - 2805 kj/mol

          Estimate the efficiency of aerobic cellular respiration of a molecule of glucose:
a. energy of formation of atp from adp: ~ + 57 kj/mol
b. energy of combustion of glucose: ~ - 2805 kj/mol
        

Added by Ross D.

Biology for AP Courses
Biology for AP Courses
Julianne Zedalis, John Eggebrecht
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Estimate the efficiency of aerobic cellular respiration of a molecule of glucose: a. energy of formation of atp from adp: ~ + 57 kj/mol b. energy of combustion of glucose: ~ - 2805 kj/mol
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Transcript

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00:01 So today, we're asked to estimate the efficiency of aerobic cellular respiration, and we're given two processes.
00:07 The first one is the conversion of adp to atp, and this has a yield of positive 57 kilojoules per mole.
00:15 We're also told that for the combustion of glucose, this is negative 2 ,805 kilojoules per mole.
00:21 So we know that our formula for energy efficiency is the energy that we have to put in divided by the energy produced.
00:30 Okay? and so we know that in cellular respiration, our theoretical yield is 36 atp...
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